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Customers come to a single line served by two servers. The time between arrivals is exponentially distributed with an average time between arrivals of 1/λ=15 time [login to view URL] service time of a job is exponentially distributed with an average of 1/μ=20 time units.
Customers are serviced for at most 1.5 time units at one time. If they need more service time, they go to the back of the queue of waiting customers (round robin); otherwise they exit the system.
Compare the avg time in the system excluding their service time (exit time-arrival time-service time) for a customer in categories of for the service requirement jobs of 0 to 7 units, 7+ to 14 units, 14+ to 21, 21 units after 10,000 customers exit the system.
Show enough information for the first 15 customers that enter the system to enable to debug the program.
Repeat the above but change the service to FCFS. (A simple way of doing this with little change to your program is to change the quantum of service to be1000.)
Project ID: #34987804
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hi. I am excellent mathematica and Programmer. I have many experiences in programming using VB, c++/c/c#, Java, python, matlab.... let's discuss more detail through chat. thanks and regards.
Hi Teck Nice to meet you Algorithm and Java Expert with 10 years experience Let me know more details Thanks
hELLO THERE, Hope you are doing well *** YOU WANT A JAVA EXPERT DEVELOPER.*** we are an expert web developer with an experience of JAVA, PHP, Laravel, CI, for more than 4 + years. I can assure you 100% that we are fu More
Hi, Greetings! I am expert Java Developer and have great experience with DSA and core JAVA. I will implement your Problem case FCFS( First Come First Serve) I have hands-on expertise in following DSA Problem:- 1-Qu More
